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Should Wizard Hit Mommy? Summary Class 12th English || Theme || Characters || Gist of the story Vistas class 12 English

Should Wizard Hit Mommy? Summary   John Hoyer Updike (March 18, 1932 – January 27, 2009) was an American novelist, poet, short-story writer, art critic, and literary critic. One of only three writers to win the Pulitzer Prize for Fiction more than once. Updike published more than twenty novels, more than a dozen short-story collections, as well as poetry, art and literary criticism and children’s books during his career. Introduction Little children love to hear stories from their parents at bedtime. Such stories are mostly fables and have no logic behind them. Many a time, parents make up stories out of their own head. Little children take them as literally true. But as the child grows up, he becomes inquisitive. He begins to ask many questions. He wants to know why and how certain things happen. He wants to know the reason behind things. Sometimes parents take this questioning of the child as an affront. They try to discourage it. They want the child to accept as true whatever is sai

A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)

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Question : A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.) Answer :  Actual depth of the bulb in water,  d1 = 80 cm = 0.8 m Refractive index of water, μ =1.33 The given situation is shown in the following figure: Where, i = Angle of incidence  r = Angle of refraction = 90° Since the bulb is a point source, the emergent light can be considered as a circle of  radius, R= AC/2 = AO =OB Using Snell’ law, we can write the relation for the refractive index of water as: Using the given figure, we have the relation: tan i = OC / OB =R/d1 ∴R = tan 48.75° × 0.8 = 0.91 m ∴Area of the surface of water = Ï€R² = Ï€ (0.91)² = 2.61 m² Hence, the area of the surface of water through which the light from the bulb can  emerge is approximately 2.61 m².

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