Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation

Ques: Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: 
                     N2ā€‹ +  H2 ā€‹ (g)ā†’2 NH3 ā€‹ 
 (i) Calculate the mass of ammonia produced if 2.00Ɨ10 2 g di nitrogen react with 1.00Ɨ10 3 g of dihydrogen. 

(ii) Will any of the two reactants remain un reacted?

(iii) If yes, which one and what would be its mass?

Ans: (i) 28.0 g of N2 require 6.0 g of H2 to produce =34.0 g of NH 
ā€‹ 
 
2.00 Ɨ 10Ā³ g of N2 will produce = 28/34 Ɨ2.00Ɨ10Ā³g of NH3   =2.43Ɨ10Ā³ g of NH3 
               =2430 g NH3

ā€‹ 
 (ii) Yes, dihydrogen will remain un reacted to some extent. 

(iii) Amount of hydrogen that remains un reacted.

28.0 g of Nrequire 6.0 g of H2
ā€‹ 
 2.00 gƗ10Ā³ g of Nwill require = 6.0 / 28.0 Ɨ 2.00Ɨ10Ā³ of H2  =428.5 g of H2
ā€‹ 
 āˆ“ Amount of hydrogen that remains un reacted =[1.00Ɨ10 āˆ’428.5]  g = 571.5 g.

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