Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation
Ques: Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
N2 + H2
(g)→2 NH3
(i) Calculate the mass of ammonia produced if 2.00×10
2
g di nitrogen react with 1.00×10
3
g of dihydrogen.
(ii) Will any of the two reactants remain un reacted?
(iii) If yes, which one and what would be its mass?
Ans: (i) 28.0 g of N2 require 6.0 g of H2 to produce =34.0 g of NH
2.00 × 10³ g of N2 will produce = 28/34 ×2.00×10³g of NH3 =2.43×10³ g of NH3
=2430 g NH3
(ii) Yes, dihydrogen will remain un reacted to some extent.
(iii) Amount of hydrogen that remains un reacted.
28.0 g of N2 require 6.0 g of H2
2.00 g×10³ g of N2 will require = 6.0 / 28.0 × 2.00×10³ of H2 =428.5 g of H2
∴ Amount of hydrogen that remains un reacted =[1.00×10 −428.5] g = 571.5 g.
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