Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation
Ques: Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
N2ā + H2 ā
(g)ā2 NH3 ā
(i) Calculate the mass of ammonia produced if 2.00Ć10
2
g di nitrogen react with 1.00Ć10
3
g of dihydrogen.
(ii) Will any of the two reactants remain un reacted?
(iii) If yes, which one and what would be its mass?
Ans: (i) 28.0 g of N2 require 6.0 g of H2 to produce =34.0 g of NH
ā
2.00 Ć 10Ā³ g of N2 will produce = 28/34 Ć2.00Ć10Ā³g of NH3 =2.43Ć10Ā³ g of NH3
=2430 g NH3
ā
(ii) Yes, dihydrogen will remain un reacted to some extent.
(iii) Amount of hydrogen that remains un reacted.
28.0 g of N2 require 6.0 g of H2
ā
2.00 gĆ10Ā³ g of N2 will require = 6.0 / 28.0 Ć 2.00Ć10Ā³ of H2 =428.5 g of H2
ā
ā“ Amount of hydrogen that remains un reacted =[1.00Ć10 ā428.5] g = 571.5 g.
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