Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation

Ques: Di nitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: 

                     N2​ +  H2 ​ (g)→2 NH3 ​ 

 (i) Calculate the mass of ammonia produced if 2.00×10 2 g di nitrogen react with 1.00×10 3 g of dihydrogen. 

(ii) Will any of the two reactants remain un reacted?

(iii) If yes, which one and what would be its mass?

Ans: (i) 28.0 g of N2 require 6.0 g of H2 to produce =34.0 g of NH 

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2.00 × 10³ g of N2 will produce = 28/34 ×2.00×10³g of NH3   =2.43×10³ g of NH3 

               =2430 g NH3

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 (ii) Yes, dihydrogen will remain un reacted to some extent. 

(iii) Amount of hydrogen that remains un reacted.

28.0 g of N2 require 6.0 g of H2

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 2.00 g×10³ g of N2 will require = 6.0 / 28.0 × 2.00×10³ of H2  =428.5 g of H2

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 ∴ Amount of hydrogen that remains un reacted =[1.00×10 −428.5]  g = 571.5 g.