Find out the following in the electric circuit given below in the figure:

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Ques: Find out the following in the electric circuit given in figure:


(a) Effective resistance of two 8 Ω resistors in the combination,

(b) Current flowing through 4 Ω resistor,

(c) Potential difference across 4 Ω resistance,

(d) Power dissipated in 4 Ω resistor, 

(e) Difference in ammeter readings, if any.

Ans: (a) Effective resistance, the two 8 Ω resistors in parallel,

R = 8×8 / 8+8
   = 4

(b) equivalent resistance = 4 + R = 8 Ω

So, current through 4 Ω = I = V/R = 8/8 = 1A
 
(c) Potential difference = V = IR = 1×4 = 8 V

(d) Potential dissipated = I²R = I² × 4 = 4 V

(e) No difference, since the ammeters are connected in series and the same amount if current pass through them, so the reading of both the ammeters will be same. 


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