Find out the following in the electric circuit given below in the figure:

Ques: Find out the following in the electric circuit given in figure:


(a) Effective resistance of two 8 Ω resistors in the combination,

(b) Current flowing through 4 Ω resistor,

(c) Potential difference across 4 Ω resistance,

(d) Power dissipated in 4 Ω resistor, 

(e) Difference in ammeter readings, if any.

Ans: (a) Effective resistance, the two 8 Ω resistors in parallel,

R = 8×8 / 8+8
   = 4

(b) equivalent resistance = 4 + R = 8 Ω

So, current through 4 Ω = I = V/R = 8/8 = 1A
 
(c) Potential difference = V = IR = 1×4 = 8 V

(d) Potential dissipated = I²R = I² × 4 = 4 V

(e) No difference, since the ammeters are connected in series and the same amount if current pass through them, so the reading of both the ammeters will be same. 






Comments

Popular posts from this blog

Upstox referral link

QUANTUM NUMBERS (Principal, Azimuthal, Magnetic and Spin)

Diagonal Relationship between Beryllium and Aluminium || Relation between Beryllium and Aluminium

S-Block Elements || S-block element class 11 chapter 8 || Group 1A, 2A elements || S block elements chapter 8 notes class 11 || Chemistry ||