Find out the following in the electric circuit given below in the figure:
Ques: Find out the following in the electric circuit given in figure:
(a) Effective resistance of two 8 Ω resistors in the combination,
(b) Current flowing through 4 Ω resistor,
(c) Potential difference across 4 Ω resistance,
(d) Power dissipated in 4 Ω resistor,
(e) Difference in ammeter readings, if any.
Ans: (a) Effective resistance, the two 8 Ω resistors in parallel,
R = 8×8 / 8+8
= 4
(b) equivalent resistance = 4 + R = 8 Ω
So, current through 4 Ω = I = V/R = 8/8 = 1A
(c) Potential difference = V = IR = 1×4 = 8 V
(d) Potential dissipated = I²R = I² × 4 = 4 V
(e) No difference, since the ammeters are connected in series and the same amount if current pass through them, so the reading of both the ammeters will be same.
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