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Diagonal Relationship between Beryllium and Aluminium || Relation between Beryllium and Aluminium

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  Diagonal Relationship between Beryllium and Aluminium The ionic radius of Beryllium (Be 2+) is estimated to be nearly 31 pm; the charge/radius ratio Or e/m ratio is nearly the same as that of the Al 3+ ion. Hence beryllium resembles aluminium in these ways. Some of the similarities are given below: » Like Aluminium, Beryllium(be) is not readily attacked by acids H+ donor because of the formation of an oxide film on the surface of the metal by reacting with oxygen, i.e. they are rendered passive by nitric acid. » Beryllium hydroxide[[Be(OH)4]2] dissolves in excess of alkali to give a beryllate ion, [ Be(OH)4]2– just as aluminium hydroxide[Al(OH)3] gives aluminate ion, [Al(OH)4] » The chlorides of metals beryllium and aluminium have Cl– bridged chloride structure in vapour phase. Both the chlorides are soluble in organic solvents and are strong as Lewis acids They are used as Friedel Craft catalysts. » Beryllium(Be) and aluminium(Al) ions have strong tendency to form complexes, (Be...
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Simple Calculator using Tkinter

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import tkinter as tk root = tk.Tk() root.title('BASIC CALCULATOR') root.geometry('640x480+300+300') root.resizable(False, False) title = tk.Label(  root,  text='Simple Calculator',  font=('Timesnewroman 18 bold'),  bg='green',  fg='#AB1' ) var1=tk.DoubleVar() var2=tk.DoubleVar() var1_label = tk.Label(root, text='Number1: ') var1_inp = tk.Entry(root, textvariable=var1) var2_label = tk.Label(root, text='Number: ') var2_inp = tk.Entry(root, textvariable=var2) plus_btn = tk.Button(root, text=' + ') minus_btn = tk.Button(root, text=' - ') mul_btn=tk.Button(root,text='*') divide_btn=tk.Button(root,text='/') output_var = tk.StringVar(value='') output_line = tk.Label(  root,  textvariable=output_var,  anchor='w',  justify='left' ) title.grid(columnspan=4) var1_label.grid(row=10,column=0) var1_inp.grid(row=10,column=1) var2_label.grid(row=10,column=2) var2_inp.grid(row=10,colu...
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Computer science MCQ questions Class 12 Python

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 SECTION-A 1. When reading a file line by line, the exact contents can be printed by: (A) Using readline ( ) (B) Using readlines ( ) (C) Using ‘,’ after every print statement (D) Both (A) & (B) 2. Choose the correct Python expression for the following mathematical expressions p+q/(r+s)4 (A) p+q / math.pow ((r+s), 4) (B) p+q/(r+s)^4 (C) p+q / math.pow (r+s,4) (D) (p+q) / math.pow (r+s) 3. Identify the correct statement for opening text file data.txt in total folder of c:drive in read mode. (A) F = open (“c:\\total\\data.txt”, “r”) (B) F = open (“c:\total\data.txt”, r) (C) F = open (“c:\total\data.txt”) (D) F = open (“\total\data.txt”, “r”) 4. A valid combination of atoms and operators forms a Python (A) Statement (B) Expression (C) Condition (D) None of these. 5. The default file open mode in Python is (A) Write (B) Read (C) Append (D) Read/write 6. In Python, a block is executed in an .................... (A) Function (B) Module (C) Py file (D) Execution frame 7. Consider ...
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  -  GT vs CSK  - Tushar Deshpande, the first-ever impact sub, proves too expensive. Williamson tears his ACL -  LSG vs DC  - Mark Wood fifer decimates Delhi -  RCB vs MI  - Back at Chinnaswamy, RCB smash MI. Kohli and Faf both got fifties -  CSK vs LSG  - CSK win a high scoring thriller by 12 runs. The difference - Dhoni's two sixes at the death -  KKR vs RCB  - Visitors outdone by spin. Suyash Sharma gets 3 on debut. Varun takes 4 and Shardul scores a match-winning 50 -  MI vs CSK  - Welcome back, Ajinkya Rahane. Scores his fastest IPL fifty -  GT vs KKR  - The Rinku game. Nothi ng more to say -  RCB vs LSG  - Pooran, Stoinis chase down 212. Avesh throws his helmet. Gambhir shushes the crowd. Harshal's failed mankad attempt -  DC vs MI  - MI win off the final ball, running 2 runs. Although Nortje nails 6 out of 6 Yorkers -  RR vs CSK  - Vintage Dhoni almost wins CSK an improbable g...
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Phosphorus and chlorine form two compounds.The first compound contains 22.54% by mass of phosphorus and 77.46% by mass of chlorine. In the second compound the percentages are 14.88 for phosphorus and 85.12 for chlorine. Show that these data are consistent with the law of multiple proportions.

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Ques : Phosphorus and chlorine form two compounds The first compound contains 22.54% by mass of phosphorus and 77.46% by mass of chlorine. In the second compound the percentages are 14.88 for phosphorus and 85.12 for chlorine. Show that these data are consistent with the law of multiple proportions. Ans : In the first compound,        Percentage of phosphorus = 22.54         Percentage of chlorine = 77.46 Thus, 22.54 g of phosphorus combines with 77.46 g chlorine. In the second compound,        Percentage of phosphorus = 14.88        Percentage of chlorine = 85.12 Thus, 14.88 g of phosphorus combine with 85.12 g of chlorine. Let us fix the mass of phosphorus as 1 g and find the different masses of chlorine which combine with 1 g of phosphorus in two compounds. In the first compound,      Mass of chlorine which combines with 22.54 g of phosphorus = 77.46 g     The mass of chlorin...
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