Dimensional formula checking for v²= 2 g h

» Checking dimensional correctness for v²= 2 g h

LHS = v² = [L T ^-1]² = [L² T ^-2]

RHS = 2 g h = 2 [L T ^-1][L] = [L² T^-2]

             »LHS = RHS

So, the LHS= RHS. 

HENCE, the given formula is dimensionally correct. 

» Checking dimensional correctness for v = u+ at

LHS = v = [L T ^-1] 

RHS = u + at=  [L T ^-1] + [L T^-2][T] 

                     = [L T^-1]

             »LHS = RHS

So, the LHS= RHS. 

HENCE, the given formula is dimensionally correct. 





Comments

Popular posts from this blog

Distinction between Electromagnetic Waves and Matter Waves

QUANTUM NUMBERS (Principal, Azimuthal, Magnetic and Spin)

Diagonal Relationship between Beryllium and Aluminium || Relation between Beryllium and Aluminium

Changing Trends And Career in Physical Education Solutions || Objective Type Questions || Objective Answers Chapter 1 Class 11 Solution || Physical Education ||

Math question