Three oxides of lead on analysis were found to contain lead as under:(i) 3.45 g of yellow oxide contains 3.21 g of lead. (ii) 1.195 g of brown oxide contains 1.035 g of lead. (iii) 1.77 g of red oxide contains 1.61 g of lead. Show that these data illustrate law of multiple proportions.

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Ques: Three oxides of lead on analysis were found to contain lead as under:

(i) 3.45 g of yellow oxide contains 3.21 g of lead.

(ii) 1.195 g of brown oxide contains 1.035 g of lead.

(iii) 1.77 g of red oxide contains 1.61 g of lead. Show that these data illustrate law of multiple proportions.

Ans: The amounts of lead and oxygen in three oxides are :

(i) Yellow oxide : Mass of lead = 3.21 g

Mass of oxygen = 3.45 - 3.21

                             = 0.24 g 

(ii) Brown oxide : Mass of lead = 1.035 g

                            Mass of oxygen = 1.195 - 1.035

                                                         = 0.160 g

(iii) Red oxide: Mass of lead = 1.61 g

                         Mass of oxygen = 1.77 – 1.61

                                                      = 0.16 g

Let us fix the mass of lead as 1 g and calculate the different weights of oxygen which combine with 1 g of lead in these oxides.

(i) Yellow oxide

     Mass of oxygen which combines with 3.21 g of lead = 0.24 g

     Mass of oxygen which combines with 1 g of lead = 0.24 / 3.21= 0.075 g

(i i) Brown oxide

    Mass of oxygen which combines with 1.035 g of lead = 0.160 g

    Mass of oxygen which combines with 1 g of lead = 0.160 / 1.035 = 0.15 g

(i i i) Red oxide

     Mass of oxygen which combines with 1.61 g of lead = 0.16 g

     Mass of oxygen which combines with 1 of  lead = 0.16 / 1.61 = 0.10 g  (IITIAN) 

The ratio of different masses of oxygen which combine with same mass of lead (1 g) in these oxides is :

               0.075 : 0.15 : 0.10

                   3    :    6    :   4

This is a simple ratio.

Hence, the data illustrate the law of multiple proportions.


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